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+
+
+//example 11.3
+//calculate
+//capacity of siphon
+//head required in oggy spillway
+//length of oggy weir required
+clc;funcprot(0);
+//given
+t=6;          //tail water elevation
+h=1;          //heigth of siphon spillway
+w=4;          //width of siphon spillway
+hw=1.5;       //head water elevation
+C=0.6;        //coefficient of discharge
+Co=2.25;      //coefficient of discharge of oggy spillway
+lo=4;         //length of oggy spillway
+hc=1.5;       //head on weir crest
+g=9.81;       //acceleration due to gravity
+
+//part (a)
+Q=C*h*w*(2*g*(t+hw))^0.5;
+Q=round(Q*10)/10;
+mprintf("capacity of siphon=%f cumecs.",Q);
+
+//part (b)
+h1=(Q/(Co*lo))^(2/3);
+h1=round(h1*100)/100;
+mprintf("\nhead required in oggy spillway=%f m",h1);
+
+//part (c)
+L=Q/(Co*(hc)^1.5);
+L=round(L*100)/100;
+mprintf("\nlength of oggy weir required=%f m.",L);