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+clc
+clear
+//Input data
+Ef=200//Energy released per fission in MeV
+Er=32*10^6//Energy produced by the reactor in W
+e=1.6*10^-19//Charge of electron in Coulumb
+
+//Calculations
+n=(Er/(Ef*10^6*e))/10^18//Number of U235 nuclei needed to produce an energy of 32*10^6 J/s *10^18
+
+//Output
+printf('%3.0f*10^18 U235 nuclei are needed to produce an energy of 32*10^6 J/s',n)