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+//Chapter-5, Example 5.26, Page 186
+//=============================================================================
+clc
+clear
+//INPUT DATA
+Z1=10+(%i*15);//impedance in ohms
+Z2=6-(%i*8);//impedance in ohms
+I=15;//current in A
+//CALCULATIONS
+I1=((Z2)/(Z1+Z2))*(I);//using current division rule
+I2=((Z1)/(Z1+Z2))*(I);//using current division rule
+i1=abs(I1);//magnitude of current 1
+i2=abs(I2);//magnitdude of current 2
+P1=((i1)^2)*(Z1(1));//power consumed by branch 1
+P2=((i2)^2)*(Z2(1));//power consumed by branch 2
+mprintf("Thus power consumed by branches 1 and 2 are %3.2f W and %4.1f W respectively",P1,P2);
+//=================================END OF PROGRAM======================================================================================================