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+//Chapter-4, Example 4.10, Page 137
+//=============================================================================
+clc
+clear
+//INPUT DATA
+f=50;//freq in c/s
+I=20;//current in A
+Im=I/sqrt(2);
+t=0.0025;//time in sec
+//equation for instantaneous emf
+i=(20*sqrt(2))*sin(2*%pi*f*t);
+t1=0.0125;
+i1=(20*sqrt(2))*sin(2*%pi*f*t1);
+i2=14.14;
+x=(i2)/(20*(sqrt(2)));
+y=asin(x);
+z=(2*%pi*50);
+t=y/z;
+mprintf("current when t is 00025 sec and 0.0125 sec are %d A and %d A respectively\n",i,i1);
+mprintf("time when value of instantaneous cureent 14.14 is %g sec",t);
+//note:in textbook for sub div (c) square root has not taken for maximum value computed
+//=================================END OF PROGRAM==============================