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+//Chapter-1,Example 1_14,Page 1-41
+clc()
+
+//Given Data:
+n=4             //4th dark ring
+m=12            //m=n+p
+D4=0.4*10^-2    //Diameter of 4th ring
+D12=0.7*10^-2   //Diameter of 12th ring
+
+//Calculations:
+
+//(Dn+p)^2-Dn^2=4*p*lam*R
+//Solving, (D12^2-D4^2)/(D20^2-D4^2)
+//We get above value =1/2. Hence
+D20=sqrt(2*D12^2-D4^2)      //Diameter of 20th ring
+printf('Diameter of 20th ring is =%.5f m \n',D20)