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+
+clc
+clear
+//Input data
+tb=850;//The bed temperature in degree centigrade
+CV=25;//The calorific value of the fuel in MJ/kg
+A=9.5;//The stoichiometric air fuel ratio by mass
+E=20;//The amount of excess air used in %
+F=4.8;//The total fueling rate in MW
+p=0.3145;//The density of air at bed temperature in kg/m^3
+f=2;//The firing rate in MW/m^2
+v=2.7;//The fluidizing velocity in m/s
+
+//Calculations
+P=F/f;//Planform area in m^2
+m=(F*1000)/(CV*1000);//Fuel burning rate in kg/s
+ma=A*(1+(E/100))*m;//Mass flow rate of air in kg/s
+Pa=ma/(p*v);//Planform area in m^2
+
+//Output
+printf('(a) The planform area = %3.1f m^2 \n (b) Fuel burning rate = %3.3f kg/s \n Air flow rate = %3.4f kg/s \n Planform area = %3.2f m^2 ',P,m,ma,Pa)
+