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+clc,clear
+printf('Example 5.22\n\n')
+
+V=600
+VA=60*10^3
+I_sc=210
+V_oc=480
+I_f=10
+R_a=0.2
+
+I=VA/V //VA=V*I and alternator is single phase
+I_a=I
+
+Z_s=V_oc/I_sc //Synchronous Impedance
+X_s=sqrt(Z_s^2-R_a^2) //SYnchronous Reactance
+printf('Synchronous impedances is %f ohms and synchronous reactance is %f ohms\n',Z_s,X_s)
+
+//PART (i)
+phi1=acos(0.8) //and lagging
+E1=sqrt((V*cos(phi1)+I_a*R_a)^2+(V*sin(phi1)+I_a*X_s)^2) //plus sign for lagging power factor
+regulation1=100*(E1-V)/V
+printf('\nRegulation at 0.8 lagging pf is %.2f percent ',regulation1 )
+
+//PART (ii)
+phi2=acos(1)
+E2=sqrt((V*cos(phi2)+I_a*R_a)^2+(V*sin(phi2)+I_a*X_s)^2)
+regulation2=100*(E2-V)/V
+printf('\nRegulation at UNITY pf is %.2f percent ',regulation2 )
+
+//PART (iii)
+phi3=acos(0.6) //and leading
+E3=sqrt((V*cos(phi3)+I_a*R_a)^2+(V*sin(phi3)-I_a*X_s)^2) //minus sign for leading power factor
+regulation3=100*(E3-V)/V
+printf('\nRegulation at 0.6 leading pf is %.2f percent ',regulation3 )