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+clc,clear
+printf('Example 2.20\n\n')
+
+P=4, I_a1= 50, N_1=2000, V=230
+
+//phi_1 is proportioanl to total ampere-turns produced by field coils
+//phi_1 (prop.) I_a1*P*n (prop.) 200*n (1)
+
+//After reconnection, phi_2 proportional to ampere turns divided as follows
+//phi_2 (prop.) [I_a2/2*2*n + I_a2/2*2*n] (prop.) 2*n*I_a2 (2)
+
+// Dividing (1) and (2) , (phi_1/phi_2)=100 / I_a2 (3)
+
+//T (prop.) phi*I_a AND T (prop.) N^2 (4),(5)
+//therefore N^2 (prop.) phi*I_a (6)
+
+//N (prop.) E_b/phi (prop.) 1/phi ..
+//Because drops across windings can be neglected, E_b1=E_b2
+//therefore N (prop.) 1/phi (7)
+
+//Using (7) and (6) phi^3 (prop.) 1/I_a (8)
+
+//combining (3) and (8)
+I_a2 = (50*100^3)^(1/4) //new armature current
+printf('New armature current= %.3f A\n',I_a2)
+//combining (6) and (7) , N^3 (prop.) I_a1
+N_2=N_1 *(I_a2/I_a1)^(1/3)
+printf('New motor speed =%.3f r.p.m',N_2)