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diff --git a/1938/CH2/EX2.19/2_19.jpg b/1938/CH2/EX2.19/2_19.jpg
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diff --git a/1938/CH2/EX2.19/2_19.sce b/1938/CH2/EX2.19/2_19.sce
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+clc,clear
+printf('Example 2.19\n\n')
+
+V=110
+P=4
+R_a = 0.1,R=0.01  //A resistance of 0.01 ohms
+R_se=R+R
+
+//case(i)
+I_1=50, I_a1=I_1
+N_1=700
+E_b1 = V -I_a1*(R_a + R_se)
+
+//T (prop.) phi*I_a   from torque equation                                     (1)
+
+//phi_1 (prop.) I_a1                                                           (2)
+//case(ii) when I_a2 gets divided to half
+//phi_2 (prop.) I_a2/2                                                         (3)
+
+//combining (1)(2)(3) and T1=T2
+I_a2 = sqrt(2*I_a1^2)
+R_se_eqvt=(R*R)/(R+R)   //Equavalent of parallel combination
+E_b2 = V - I_a2*R_a - I_a2* R_se_eqvt
+
+//Using speed equation N (prop.) E_b / phi  and using (2) and (3)
+N_2 = N_1 *( E_b2/E_b1) *(I_a1/(I_a2/2))
+printf('Speed after reconnection = %.3f r.p.m\n\n',N_2)