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+// Theory and Problems of Thermodynamics
+// Chapter 5
+//Second Law of Thermodynamcis
+// Example 13
+
+clear ;clc;
+
+//Given data
+N = 1         // number of moles of nitrogen
+r = 1.4       // ratio of specific heats of nitrogen at 0.1 MPa and 300 K
+P1 = 0.1      // initial state pressure in MPa
+T1 = 300      // initial state temperature in K
+P2 = 0.5      // final state pressure in MPa
+T2 = 600      // final state temperature in K
+R = 8.314     // universal gas constant J/mol/K
+
+// Calculation for determining the change in the entrophy of nitrogen
+// del_S  = N{Cp ln(T2/T1) - R ln(P2/P1)}
+del_S  = N*{(R*r/(r -1))*log(T2/T1) - R*log(P2/P1)}
+
+// Output Results
+mprintf('The change in entrophy of nitrogen = %5.3f kJ/mol K' ,del_S)
+