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+// Scilab code Ex5.27: Pg:233 (2008)
+clc;clear;
+Lambda = 6000e-08;    //Mean wavelength of light, cm
+a = 200;    // Diameter of the objective of a telescope, cm
+a_prime = 0.2;    // Aperture of the eye lens, cm
+f = 2.54;    // Focal length of eye-piece, cm
+theta = 1.22*Lambda/a;    // The smallest angular separation resolvable by a telescope objective of diameter a, radian
+theta_prime = 1.22*Lambda/a_prime;    // The smallest angle that can be resolved by the eye where a^' is the aperture of the eye, radian
+MP = theta_prime/theta;    // Magnifying power of the telescope
+// As MP = F/f, solving for F
+F = MP*f;    // The minimum focal length of the objective, cm
+printf("\nThe minimum focal length of the objective if the full resolving power of the telescope is to be utilized = %4d cm", F);
+
+// Result 
+// The minimum focal length of the objective if the full resolving power of the telescope is to be utilized = 2540 cm 
+\ No newline at end of file