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+
+clear
+ clc
+//to find forces exerted on the ladder by the ground and by the wall
+
+
+// GIVEN::
+
+//refer to figure 9-23(a) from page no. 189
+//length of ladder
+L = 12//in meters
+//mass of ladder
+m = 45//in kg
+//distance of upper end of ladder above the ground
+h = 9.3//in meters
+//mass of firefighter
+M = 72//in kg
+//acceleration due to gravity
+g = 9.8//in m/s^2
+
+// SOLUTION:
+
+//refer to figure 9-23(b) from page no. 189
+//distance from the wall to the foot of ladder
+a = sqrt(L^2 - h^2)//in meters
+//considering equillibrium conditions
+//finding normal reaction by ground
+N = (M+m)*g//in N
+//force exerted on ladder by the wall
+Fw = (g*a*(M/2 + m/3))/h//in N
+N = round(N)
+Fw = round(Fw)
+printf ("\n\n Distance from the wall to the foot of ladder a = \n\n %.1f m",a);
+//answer is slightly different than book.But answer of scilab program is same as that of calculator
+printf ("\n\n Forces exerted on the ladder by the ground N = \n\n %3i N",N);
+//answer is slightly different than book.But answer of scilab program is same as that of calculator
+printf ("\n\n Forces exerted on the ladder by the wall Fw = \n\n %3i N",Fw);