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+// Exa 5.5
+clc;
+clear;
+close;
+// Given expression Vout= 10*(V2-V1)
+// For a differential amplifier circuit
+// Vout= Rf/R*(V2-V1)
+// Compare the above expression with the given expression for the output, we have
+RfbyR= 10;
+R=10;// minimum value of resistancce to be used in kohm
+Rf= RfbyR * R;// in k ohm
+disp(Rf,"Value of Rf in k ohm");