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+// Exa 11.5
+clc;
+clear;
+close;
+//given data
+R1= 2.5;// in kohm
+R1= R1*10^3;// in ohm
+R2= 1;// in kohm
+R2= R2*10^3;// in ohm
+V_REF= 1.25;// in volt
+I= V_REF/R2;// in amp
+// This current also flows through R1. So the output voltage
+V_out= I*(R1+R2);// in volt
+disp(V_out,"Output voltage in volt")