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+// Exa 1.5
+clc;
+clear;
+close;
+// Given data
+format('v',7)
+V_CC= 15;// in volt
+V_EE= 15;// in volt
+V_BE= 0.7;// in volt
+R_C= 1;// in M ohm
+R_C= R_C*10^6;// in ohm
+R_E= R_C;// in ohm
+
+Bita_ac= 100;
+I_E = (V_EE-V_BE)/(2*R_E);// in amp
+re_desh= (26*10^-3)/I_E;// in ohm
+A_d = R_C/re_desh;
+disp(A_d,"Voltage gain ");
+Z_in= 2*Bita_ac*re_desh;// in ohm
+disp(Z_in*10^-6,"Input impedence in M ohm");
+Z_out= R_C;// in ohm
+disp(Z_out*10^-6,"Output impedence in M ohm");
+A_cm= R_C/(2*R_E+re_desh);
+CMRR= A_d/A_cm;
+disp(CMRR,"Common-mode rejection ratio");
+disp("When v_in is zero, the ac output voltage is zero. So total output voltage at the quiescent value in volt")
+I_C=I_E;
+V_out= V_CC-I_C*R_C;// in volt
+disp(V_out);
+// when v_in = 1
+v_in= 1;// in mV
+v_in= v_in*10^-3;// in volt
+disp("When v_in = 1 mv, the ac output voltage in volt");
+v_out= A_d*v_in;
+disp(v_out);
+
+// Note : Answer of CMRR in the book is wrong due to wrong calculation of A_cm