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+//CHAPTER 5 ILLUSRTATION 6 PAGE NO 165
+//TITLE:Inertia Force Analysis in Machines
+clc
+clear
+pi=3.141
+D=.25// diameter of horizontal steam engine in m
+N=180// speed of the engine in rpm
+d=.05// diameter of piston in m
+P=36000// power of the engine in watts
+n=3// ration of length of connecting rod to the crank radius
+p1=5.8*10^5// pressure on cover end side in N/m^2
+p2=0.5*10^5// pressure on crank end side in N/m^2
+teeta=40// angle of inclination of crank in degrees
+m=45// mass of flywheel in kg
+k=.65// radius of gyration in m
+//==============================
+Fl=(pi/4*D^2*p1)-(pi/4*(D^2-d^2)*p2)// load on the piston in N
+phi=asind(sind(teeta)/n)// angle of inclination of the connecting rod to the line of stroke in degrees
+r=1.6*D/2
+T=Fl*sind(teeta+phi)/cosd(phi)*r// torque exerted on crank shaft in N-m
+Fb=Fl*cosd(teeta+phi)/cosd(phi)// thrust on the crank shaft bearing in N
+TR=P*60/(2*pi*N)// steady resisting torque in N-m
+Ts=T-TR// surplus torque available in N-m
+a=Ts/(m*k^2)// acceleration of the flywheel in rad/s^2
+printf('Torque exerted on the crank shaft= %.3f N-m\n Thrust on the crank shaft bearing= %.3f N\n Acceleration of the flywheel= %.3f rad/s^2',T,Fb,a)