10 files changed, 224 insertions, 0 deletions
diff --git a/1835/CH10/EX10.1/Ex10_1.sce b/1835/CH10/EX10.1/Ex10_1.sce
new file mode 100755
index 000000000..811ff0a24
--- /dev/null
+++ b/1835/CH10/EX10.1/Ex10_1.sce
@@ -0,0 +1,17 @@
+//CHAPTER 10 ILLUSRTATION 1 PAGE NO 268
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+d=0.32;//Diameter of the drum in m
+qq=90;//Angle of contact in degree
+P=820;//Force applied in N
+U=0.35;//Coefficient of friction
+
+
+U1=((4*U*sind(qq/2))/((qq*(3.14/180))+sind(qq)));//Equivalent coefficient of friction
+F=((P*0.66)/((0.3/U1)-0.06));//Force value in N taking moments
+TB=(F*(d/2));//Torque transmitted in N.m
+
+printf('Torque transmitted by the block brake is %3.4f N.m',TB)
diff --git a/1835/CH10/EX10.10/Ex10_10.sce b/1835/CH10/EX10.10/Ex10_10.sce
new file mode 100755
index 000000000..47b0dd7f1
--- /dev/null
+++ b/1835/CH10/EX10.10/Ex10_10.sce
@@ -0,0 +1,26 @@
+//CHAPTER 10 ILLUSRTATION 10 PAGE NO 275
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+n=12;// Number of blocks
+q=16;//Angle subtended in degrees
+d=0.9;//Effective diameter in m
+m=2000;//Mass in kg
+k=0.5;//Radius of gyration in m
+b1=0.7;//Distance in m
+b2=0.03;//Distance in m
+a=0.1;//Distance in m
+P=180;//Force in N
+N=360;//Speed in r.p.m
+U=0.25;//Coefficient of friction
+
+Tr=((1+(U*tand(q/2)))/(1-(U*tand(q/2))))^n;//Tensions ratio
+T2=(P*b1)/(a-(b2*Tr));//Tension in N
+T1=(Tr*T2);//Tension in N
+TB=(T1-T2)*(d/2);//Torque in N.m
+aa=(TB/(m*k^2));//Angular acceleration in rad/s^2
+t=((2*3.14*N)/60)/aa;//Time in seconds
+
+printf('(i) Maximum braking torque is %3.4f Nm \n(ii) Angular retardation of the drum is %3.4f rad/s^2 \n(iii) Time taken by the system to come to rest is %3.1f s',TB,aa,t)
diff --git a/1835/CH10/EX10.2/Ex10_2.sce b/1835/CH10/EX10.2/Ex10_2.sce
new file mode 100755
index 000000000..30781cc03
--- /dev/null
+++ b/1835/CH10/EX10.2/Ex10_2.sce
@@ -0,0 +1,18 @@
+//CHAPTER 10 ILLUSRTATION 2 PAGE NO 269
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+m=120;//Mass of rider in kg
+v=16.2;//Speed of rider in km/hr
+d=0.9;//Diameter of the wheel in m
+P=120;//Pressure applied on the brake in N
+U=0.06;//Coefficient of friction
+
+F=(U*P);//Frictional force in N
+KE=((m*(v*(5/18))^2)/2);//Kinematic Energy in N.m
+S=(KE/F);//Distance travelled by the bicycle before it comes to rest in m
+N=(S/(d*3.14));//Required number of revolutions
+
+printf('The bicycle travels a distance of %3.2f m and makes %3.2f turns before it comes to rest',S,N)
diff --git a/1835/CH10/EX10.3/Ex10_3.sce b/1835/CH10/EX10.3/Ex10_3.sce
new file mode 100755
index 000000000..12f0f890d
--- /dev/null
+++ b/1835/CH10/EX10.3/Ex10_3.sce
@@ -0,0 +1,18 @@
+//CHAPTER 10 ILLUSRTATION 3 PAGE NO 270
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+S=3500;//Force on each arm in N
+d=0.36;//Diamter of the wheel in m
+U=0.4;//Coefficient of friction 
+qq=100;//Contact angle in degree
+
+qqr=(qq*(3.14/180));//Contact angle in radians
+UU=((4*U*sind(qq/2))/(qqr+(sind(qq))));//Equivalent coefficient of friction
+F1=(S*0.45)/((0.2/UU)+((d/2)-0.04));//Force on fulcrum in N
+F2=(S*0.45)/((0.2/UU)-((d/2)-0.04));//Force on fulcrum in N
+TB=(F1+F2)*(d/2);//Maximum torque absorbed in N.m
+
+printf('Maximum torque absorbed is %3.2f N.m',TB)
diff --git a/1835/CH10/EX10.4/Ex10_4.sce b/1835/CH10/EX10.4/Ex10_4.sce
new file mode 100755
index 000000000..d1d9361a1
--- /dev/null
+++ b/1835/CH10/EX10.4/Ex10_4.sce
@@ -0,0 +1,19 @@
+//CHAPTER 10 ILLUSRTATION 4 PAGE NO 271
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+a=0.5;//Length of lever in m
+d=0.5;//Diameter of brake drum in m
+q=(5/8)*(2*3.14);//Angle made in radians
+b=0.1;//Distance between pin and fulcrum in m
+P=2000;//Effort applied in N
+U=0.25;//Coefficient of friction
+
+T=exp(U*q);//Ratios of tension
+T2=((P*a)/b);//Tension in N
+T1=(T*T2);//Tension in N
+TB=((T1-T2)*(d/2))/1000;//Maximum braking torque in kNm
+
+printf('The maximum braking torque on the drum is %3.3f kNm',TB)
diff --git a/1835/CH10/EX10.5/Ex10_5.sce b/1835/CH10/EX10.5/Ex10_5.sce
new file mode 100755
index 000000000..c2d25658c
--- /dev/null
+++ b/1835/CH10/EX10.5/Ex10_5.sce
@@ -0,0 +1,19 @@
+//CHAPTER 10 ILLUSRTATION 5 PAGE NO 271
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+q=220;//Angle of contact in degree
+T=340;//Torque in Nm
+d=0.32;//Diameter of drum in m
+U=0.3;//Coefficient of friction
+
+Td=(T/(d/2));//Difference in tensions in N
+Tr=exp(U*(q*(3.14/180)));//Ratio of tensions
+T2=(Td/(Tr-1));//Tension in N
+T1=(Tr*T2);//Tension in N
+P=((T2*(d/2))-(T1*0.04))/0.5;//Force applied in N
+b=(T1/T2)*4;//Value of b in cm when the brake is self-locking
+
+printf('The value of b is %3.2f cm when the brake is self-locking \n Tensions in the sides are %3.3f N and %3.3f N',b,T1,T2)
diff --git a/1835/CH10/EX10.6/Ex10_6.sce b/1835/CH10/EX10.6/Ex10_6.sce
new file mode 100755
index 000000000..1015c4b08
--- /dev/null
+++ b/1835/CH10/EX10.6/Ex10_6.sce
@@ -0,0 +1,27 @@
+//CHAPTER 10 ILLUSRTATION 6 PAGE NO 272
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+d=0.5;//Drum diamter in m
+U=0.3;//Coefficient of friction
+q=250;//Angle of contact in degree
+P=750;//Force in N
+a=0.1;//Band width in m
+b=0.8;//Distance in m
+ft=(70*10^6);//Tensile stress in Pa
+f=(60*10^6);//Stress in Pa
+b1=0.1;//Distance in m
+
+T=exp(U*(q*(3.14/180)));//Tensions ratio
+T2=(P*b*10)/(T+1);//Tension in N
+T1=(T*T2);//Tension in N
+TB=(T1-T2)*(d/2);//Torque in N.m
+t=(max(T1,T2)/(ft*a))*1000;//Thickness in mm
+M=(P*b);//bending moment at fulcrum in Nm
+X=(M/((1/6)*f));//Value of th^2
+//t varies from 10mm to 15 mm. Taking t=15mm,
+h=sqrt(X/(0.015))*1000;//Section of the lever in m
+
+printf('Torque required is %3.2f N.m \nThickness necessary to limit the tensile stress to 70 MPa is %3.3f mm \n Section of the lever taking stress to 60 MPa is %3.1f mm',TB,t,h)
diff --git a/1835/CH10/EX10.7/Ex10_7.sce b/1835/CH10/EX10.7/Ex10_7.sce
new file mode 100755
index 000000000..a143e2dd5
--- /dev/null
+++ b/1835/CH10/EX10.7/Ex10_7.sce
@@ -0,0 +1,26 @@
+//CHAPTER 10 ILLUSRTATION 7 PAGE NO 273
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+P1=30;//Power in kW
+N=1250;//Speed in r.p.m
+P=60;//Applied force in N
+d=0.8;//Drum diameter in m
+q=310;//Contact angle in degree
+a=0.03;//Length of a in m
+b=0.12;//Length of b in m
+U=0.2;//Coefficient of friction
+B=10;//Band width in cm
+D=80;//Diameter in cm
+
+T=(P1*60000)/(2*3.14*N);//Torque in N.m
+Td=(T/(d/2));//Tension difference in N
+Tr=exp(U*(q*(3.14/180)));//Tensions ratio
+T2=(Td/(Tr-1));//Tension in N
+T1=(Tr*T2);//Tension in N
+x=((T2*b)-(T1*a))/P;//Distance in m;
+X=(P1/(B*D));//Ratio
+
+printf('Value of x is %3.4f m \n Value of (Power/bD) ratio is %3.4f',x,X)
diff --git a/1835/CH10/EX10.8/Ex10_8.sce b/1835/CH10/EX10.8/Ex10_8.sce
new file mode 100755
index 000000000..f39b7c7f6
--- /dev/null
+++ b/1835/CH10/EX10.8/Ex10_8.sce
@@ -0,0 +1,26 @@
+//CHAPTER 10 ILLUSRTATION 8 PAGE NO 274
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+m=80;//Mass of flywheel in kg
+k=0.5;//Radius of gyration in m
+N=250;//Speed in r.p.m
+d=0.32;//Diamter of the drum in m
+b=0.05;//Distance of pin in m
+q=260;//Angle of contact in degree
+U=0.23;//Coefficient of friction
+P=20;//Force in N
+a=0.35;//Distance at which force is applied in m
+
+Tr=exp(U*q*(3.14/180));//Tensions ratio
+T2=(P*a)/b;//Tension in N
+T1=(Tr*T2);//Tension in N
+TB=(T1-T2)*(d/2);//Torque in N.m
+KE=((1/2)*(m*k^2)*((2*3.14*N)/60)^2);//Kinematic energy of the rotating drum in Nm
+N1=(KE/(TB*2*3.14));//Speed in rpm
+aa=((2*3.14*N)/60)^2/(4*3.14*N1);//Angular acceleration in rad/s^2
+t=((2*3.14*N)/60)/aa;//Time in seconds
+
+printf('Time required to bring the shaft to the rest from its running condition is %3.1f seconds',t)
diff --git a/1835/CH10/EX10.9/Ex10_9.sce b/1835/CH10/EX10.9/Ex10_9.sce
new file mode 100755
index 000000000..d2a8ba2e4
--- /dev/null
+++ b/1835/CH10/EX10.9/Ex10_9.sce
@@ -0,0 +1,28 @@
+//CHAPTER 10 ILLUSRTATION 9 PAGE NO 275
+//TITLE:Brakes and Dynamometers
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+n=12;//Number of blocks
+q=15;//Angle subtended in degree
+P=185;//Power in kW
+N=300;//Speed in r.p.m
+U=0.25;//Coefficient of friction
+d=1.25;//Diamter in m
+b1=0.04;//Distance in m
+b2=0.14;//Distance in m
+a=1;//Diatance in m
+m=2400;//Mass of rotor in kg
+k=0.5;//Radius of gyration in m
+
+Td=(P*60000)/(2*3.14*N*(d/2));//Tension difference in N
+T=Td*(d/2);//Torque in Nm
+Tr=((1+(U*tand(q/2)))/(1-(U*tand(q/2))))^n;//Tension ratio
+To=(Td/(Tr-1));//Tension in N
+Tn=(Tr*To);//Tension in N
+P=((To*b2)-(Tn*b1))/a;//Force in N
+aa=(T/(m*k^2));//Angular acceleration in rad/s^2
+t=((2*3.14*N)/60)/aa;//Time in seconds
+
+printf('Minimum force required is %3.0f N \nTime taken to bring to rest is %3.1f seconds',P,t)