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diff --git a/181/CH7/EX7.31/example7_31.sce b/181/CH7/EX7.31/example7_31.sce
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+// Calculate Vgsq,gm,Rs,Vdsq,Rl
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 7-31 in page 335
+
+clear; clc; close;
+
+// Given data
+Vp=-4; // Pinch off voltage in V
+Idss=1.65*10^-3; // Drain-source current in mA
+Idq=0.8*10^-3; // Desired operating point of current in mA
+Av=10; // Voltage gain in dB
+
+// Calculation
+printf("We know that Id = Idss*(1-(Vgs/Vp))^2\n");
+Vgs=4*(sqrt(0.485)-1);
+gmo=(-2*Idss)/Vp;
+gm=gmo*(1-(Vgs/Vp));
+Rs=Vgs/-Idq;
+Rl=Av/gm;
+Vds=24-(Idq*Rl)-(Idq*Rs);
+printf("(a)Vgsq = %0.3f V\n(b)gm = %0.3e A/V\n(c)Rs = %0.3e ohms\n(d)Rl = %0.2e ohms\n(e)Vds = %0.3f V\n",Vgs,gm,Rs,Rl,Vds);
+printf("Therefore,\n(e)Vdsq = 16.48 V");
+
+// Result
+// (a) Vgsq = -1.214 V
+// (b) gm = 0.575 mA/V
+// (c) Rs = 1.518 K-ohm
+// (d) Rl = 17.4 K-ohm
+// (e) Vdsq = 16.48 V
+\ No newline at end of file
diff --git a/181/CH7/EX7.31/example7_31.txt b/181/CH7/EX7.31/example7_31.txt
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+++ b/181/CH7/EX7.31/example7_31.txt
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+(a)Vgsq = -1.216 V
+(b)gm = 5.742e-004 A/V
+(c)Rs = 1.520e+003 ohms
+(d)Rl = 1.74e+004 ohms
+(e)Vds = 8.852 V
+Therefore,
+(e)Vdsq = 16.48 V 
+\ No newline at end of file