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diff --git a/181/CH2/EX2.8/example2_8.sce b/181/CH2/EX2.8/example2_8.sce
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+// Calculate width of depletion layer
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 2-8 in page 87
+
+clear; clc; close;
+
+// Given data
+V=[10.2 0.3 0.1]; // Applied voltages in V
+epsln=16; // Constant of calculation
+A=1*10^-6; // Cross sectional area in m^2
+
+// Calculation
+alp=[1 2 3];
+for i=1:3
+    W=sqrt((V(i)*10^-10)/14.3);
+    printf("(%0.0f)Width of depletion layer for %0.2f V = %0.2e mu-m\n\n",alp(i),V(i),W);
+end
+W=[8.5 1.45];
+alp1=[1 2];
+for j=1:2
+    C_T=(epsln*10^-9)/(36*%pi*W(j));
+    printf("(%0.0f)Space charge capacitance for %0.2f mu-m = %0.2e F\n\n",alp(j),W(j),C_T);
+end
+
+// Result
+// Widths of depletion layer are: 
+// (a) 8.5 mu-m
+// (b) 1.45 mu-m 
+// (c) 0.84 mu-m respectively
+// Space charge capacitances are:
+// (a) 16.65 pF 
+// (b) 97.6 pF respectively
+\ No newline at end of file
diff --git a/181/CH2/EX2.8/example2_8.txt b/181/CH2/EX2.8/example2_8.txt
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+(1)Width of depletion layer for 10.20 V = 8.45e-006 mu-m
+
+(2)Width of depletion layer for 0.30 V = 1.45e-006 mu-m
+
+(3)Width of depletion layer for 0.10 V = 8.36e-007 mu-m
+
+(1)Space charge capacitance for 8.50 mu-m = 1.66e-011 F
+
+(2)Space charge capacitance for 1.45 mu-m = 9.76e-011 F
+
+ 
+\ No newline at end of file