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diff --git a/181/CH2/EX2.32/example2_32.sce b/181/CH2/EX2.32/example2_32.sce
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+// Find the range for R
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 2-32 in page 110
+
+clear; clc; close;
+
+// Given data
+P=250; // Maximum power dissipation in mW
+V=15; // Supply voltage in V
+
+// Caluclation
+I=(250*10^-3)/5;
+printf("Maximum permissible current = %0.3e A\n",I);
+printf("10 percent of 50mA = 5mA\n");
+I1=I-(5*10^-3);
+printf("Maximum current through diode to maintain constant voltage = %0.1e A",I1);
+
+// Result
+// Maximum current to maintain constant voltage = 45mA
+\ No newline at end of file
diff --git a/181/CH2/EX2.32/example2_32.txt b/181/CH2/EX2.32/example2_32.txt
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+Maximum permissible current = 5.000e-002 A
+10 percent of 50mA = 5mA
+Maximum current through diode to maintain constant voltage = 4.5e-002 A 
+\ No newline at end of file