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+clc
+clear
+//INPUT DATA
+d=0.26;//bore of the engine in m
+L=0.38;//stroke of the engine in m
+vc=0.0025;//clearence volume in m^3
+p1=1;//pressure in bar
+t1=313;//temperature in K
+p3=25;//pressure in bar
+v12=9.07;//volume in m^3
+
+//CALCULATIONS
+vs=(3.14*d^2*L)/4;//swept volume in m^3
+Rc=((vs+vc)/vc);//compression ratio
+no=(1-((1/Rc)^(1.4-1)))*100;//Air standard efficiency of the cycle
+p2=p1*(v12^1.4);//pressure in bar
+Rp=p3/p2;//compression pressure
+pm=(p1*Rc*((Rc^(1.4-1)-1)*(Rp-1)))/((1.4-1)*(Rc-1));//mean effective pressure in bar
+
+//OUTPUT
+printf('(a)The air standard efficiency of the cycle is %3.1f percentage \n (b)The mean effective pressure is %3.4f bar',no,pm)
+