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+//Chapter-1, Illustration 8, Page 21
+//Title: Fuels and Combustion
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+C=0.88;//Percentage composition of Carbon
+H=0.036;//Percentage composition of Hydrogen
+O=0.048;//Percentage composition of oxygen
+CO2=0.109;//Volumetric composition of CO2
+CO=0.01;//Volumetric composition of CO
+O2=0.071;//Volumetric composition of Oxygen
+N2=0.81;//Volumetric composition of Nitrogen
+M1=44;//Molecular mass of CO2
+M2=28;//Molecular mass of CO
+M3=32;//Molecular mass of O2
+M4=28;//Molecular mass of N2
+
+//CALCULATIONS
+m=(11.5*C)+(34.5*(H-(O/8)));//Theoretical air required in kg
+c1=CO2*M1;//Proportional mass of CO2
+c2=CO*M2;//Proportional mass of CO
+c3=O2*M3;//Proportional mass of O2
+c4=N2*M4;//Proportional mass of N2
+c=c1+c2+c3+c4;//Total proportional mass of constituents
+m1=c1/c;//Mass of CO2 per kg of flue gas in kg
+m2=c2/c;//Mass of CO per kg of flue gas in kg
+m3=c3/c;//Mass of O2 per kg of flue gas in kg
+m4=c4/c;//Mass of N2 per kg of flue gas in kg
+mC=((3*m1)/11)+((3*m2)/7);//Mass of carbon in kg
+md=C/mC;//Mass of dry flue gas in kg
+hc=H*9;//Hydrogen combustion in kg of H2O
+mair=(md+hc)-(C+H+O);//Mass of air supplied per kg of coal in kg
+me=mair-m;//Excess air per kg of coal in kg
+mN2=m4*md;//Mass of nitrogen per kg of coal in kg
+mact=mN2/0.768;//Actual mass of air per kg of coal in kg
+pe=(me/m)*100;//Perccentage excess air in percent
+
+//OUTPUT
+mprintf('Mass of air actually supplied per kg of coal is %3.2f kg \n Percentage of excess air is %3.2f percent',mact,pe)
+
+
+
+
+
+
+
+//==============================END OF PROGRAM=================================