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+//Exa 4.11
+clc;
+clear;
+close;
+//given data
+k=40;// in W/m degree C
+d =12*10^-3;// in meter
+t=127;// in degree C
+t_i=877;// in degree C
+t_infinite=52;// in degree C
+h= 20;// in W/m^2 degree C
+rho=7800;// in W/m^2K
+C=600;// in J/kg K
+r=d/2;// in meter
+//l_s = V/A = r/3
+l_s = r/3;
+Bi= h*l_s/k;
+// since Bi < 0.1 , hence lumped heat capacity analysis can be applied
+// (t-t_infinite)/(t_i-t_infinite) = %e^(-h*A*toh /(rho*V*C)) = %e^(-h*toh/(rho*l_s*C)) = %e^(-h*toh/(rho*C*l_s))
+toh = -log((t-t_infinite)/(t_i-t_infinite))*rho*C*l_s/h;// in sec
+disp("Time required for cooling process : "+string(toh)+" seconds or "+string(toh/60)+" minutes") \ No newline at end of file