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+//example 4
+//calculating required specific work
+clear
+clc
+Cp=1.004 //specific heat of air at constant pressure in kJ/kg-K
+Ti=290 //initial temperature in kelvins
+Pi=100 //initial pressure in kPa
+Pe=1000 //final pressure in kPa
+k=1.4 
+Te=Ti*(Pe/Pi)^((k-1)/k) //final temperature in kelvins
+we=Cp*(Ti-Te) //required specific work in kJ/kg
+printf("\n hence,specific work required is we=%.3f kJ/kg.\n",we)
+\ No newline at end of file