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+//example 6
+//work done by air
+clear
+clc
+T1=600 //initial temperature of air in K
+P1=400 //intial pressure of air in kPa
+P2=150 //final pressure in kPa
+u1=435.10 //specific internal energy at temperature T1 in kJ/kg
+sT1=7.5764 //specific entropy at temperature T1 in kJ/kg-K
+R=0.287 //gas constant in kJ/kg-K
+ds=0
+sT2=ds+sT1+R*log(P2/P1) //specific entropy at temperature T2 in kJ/kg-K
+disp('we know the values of s and P for state 2.So,in order to fully determine the state,we will use steam table')
+T2=457 //final temperature in K
+u2=328.14 //specific internal energy at temperature T2 in kJ/kg
+w=u1-u2 //work done by air in kJ/kg
+printf("\n hence,work done by air is w=%.2f kJ/kg.\n",w)
+\ No newline at end of file