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+//example 11
+//Determining the final temperature of steam
+clear
+clc
+u2=3040.4 //final internal energy in kJ/kg
+hi=u2 //in kJ/kg
+P2=1.4 //final Pressure in MPa
+disp('Since, the final pressure is given as 1.4 MPa,we know two properties at the final state and hence,final state can be determined.The temperature corresponding to a pressure of 1.4 MPa and an internal energy of 3040.4 kJ/kg is found to be ')
+T2=452 //final temperature in Celsius \ No newline at end of file