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+//ques5
+//To determine thermal efficiency of cycle
+clear
+clc
+//5-Inlet state for turbine
+//6-Exit state for turbine
+//h-Enthalpy at a state
+//s-Entropy at a state
+//from steam table
+h5=3169.1;//kJ/kg
+s5=6.7235;//kJ/kg
+s6s=s5;
+sf=0.6493;//Entropy for liquid state in kJ/kg
+sfg=7.5009;//Entropy difference in kJ/kg
+hf=191.8;//kJ/kg
+hfg=2392.8;//Enthalpy difference in kJ/kg
+x6s=(s6s-sf)/sfg;//x-factor
+h6s=hf+x6s*hfg;//kJ/Kg at state 6s
+nt=0.86;//turbine efficiency given
+wt=nt*(h5-h6s);
+//1-Inlet state for pump
+//2-Exit state for pump
+np=0.80;//pump efficiency given
+v=0.001009;//specific heat in m^3/kg
+P2=5000;//kPa
+P1=10;//kPa
+wp=v*(P2-P1)/np;//Work done in pump in kJ/kg
+wnet=wt-wp;//net work in kJ/kg
+//3-Inlet state for boiler
+//4-Exit state for boiler
+h3=171.8;//in kJ/kg from table
+h4=3213.6;//kJ/kg from table
+qh=h4-h3;
+nth=wnet/qh;
+printf('Cycle Efficiency = %.1f ',nth*100); \ No newline at end of file