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+
+
+                             // Examle 3.27
+
+                      // From the diagram (3.45) Apply KCL to the circuit
+                      // will get (V-10)/2 +(V-0)/4 +(V-8)/6 = 0
+                      // Using nodal analysis
+                      // hance we can get V= 6.91
+V=6.91;               // Voltage at the node
+I=V/(1+3);            // Current (I)
+disp(' Current (I) = '+string(I)+' Amp');
+
+
+
+
+         //  p 84          3.27
+
+