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+
+                      // Example  2.8
+
+v=120;                // Supply voltage
+p=60;                 // Power
+R=v^2/p;              // Resistance
+
+       // the combination R of bulb B & C is Rbc=240/2    i.e Rbc=120 
+       //  vb=vc
+
+Rbc=240/2;            // R of each bulb 
+k=240+120;
+vc=Rbc*(120/k);       // volt across Vc & Vb    {using Volt Divider Rule }
+va=120-40;            // volt across Va
+disp(' the Voltage across bulb A & B = '+string(vc)+' Volt');
+disp(' the Voltage across bulb C = '+string(va)+' Volt');
+vb=40;
+p=(va)^2/240+(vb)^2/240+(vc)^2/240;      //  p=pa+pb+pc   total power
+
+disp(' Totale Power Dissipated is = '+string(p)+' Watt');
+
+
+      //    p 25       2.8