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+clc
+//Chapter 4:Frequency selective networks and transformers
+//example 4.2
+//given
+//Forty decibles corresponds to a voltage ratio of 100:1 therefore since A(jwo)=1
+Ajwo=0.01
+n=5//no. of harmonics
+Q=n/(Ajwo*(n^2-1))//quality point
+mprintf('the minimum circuit Q is =Qmin = %f ',Q)