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+//chapter 10 Ex 11
+
+clc;
+clear;
+close;
+Diff=1660;
+
+y=poly(0,'y');
+x=Diff+y; //equation 1,given difference
+x=(125/75)*y; //equation 2
+for y=1:5000
+ if Diff+y ==(125/75)*y
+ mprintf("y=%i \n ",y);
+ break
+ end
+end
+disp("substitute value of y in any one of the above equations to find x");
+x=(125/75)*y;
+
+ans=[x y];
+printf("\n Thus the two numbers are %d and %d",ans(1),ans(2));