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+// Scilab code Ex5.29: Pg 189 (2008)
+clc; clear;
+V_2 = 60;                         // Output voltage, V
+V_1 = 240;                        // Input voltage, V
+N_2 = 500;                        // Secondary turns
+// Part (a)
+// For simplicity let V_1/V_2 = N_1/N_2 = k
+k = V_1/V_2                      // Turns ratio
+// Part (b)
+// Since V_1/V_2 = N_1/N_2, solving for N_1
+N_1 = k*N_2;                       // Primary turns
+printf("\nThe required turns ratio = %1d:1", k)
+printf("\nThe number of primary turns = %4d", N_1)
+
+// Result
+// The required turns ratio = 4:1
+// The number of primary turns = 2000