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+//example-5.5
+//page no-146
+//given
+//wavelength of X-ray
+lambda=1.54  //A
+//diameter of powder camera
+D=114.6  //mm
+//radius of powder camera
+R=D/2  //mm
+//value of l
+l1=86
+l2=100
+l3=148
+l4=180
+l5=188
+l6=232
+l7=272
+//we know that
+//theta=l/4
+//so
+theta1=l1/4*(%pi)/180   //radians
+theta2=l2/4*(%pi)/180   //radians
+theta3=l3/4*(%pi)/180   //radians
+theta4=l4/4*(%pi)/180   //radians
+theta5=l5/4*(%pi)/180   //radians
+theta6=l6/4*(%pi)/180   //radians
+theta7=l7/4*(%pi)/180   //radians
+//now values of sin (theta) and sin(theta2)
+S1=sin(theta1)
+SS1=(sin(theta1))^2
+S2=sin(theta1)
+SS2=(sin(theta1))^2
+S3=sin(theta1)
+SS3=(sin(theta1))^2
+S4=sin(theta1)
+SS4=(sin(theta1))^2
+S5=sin(theta1)
+SS5=(sin(theta1))^2
+S6=sin(theta1)
+SS6=(sin(theta1))^2
+S7=sin(theta1)
+SS7=(sin(theta1))^2
+//so the ratio can be expressed as
+//3:4:8:11:12:16:19
+printf ("from the extinction rule, we notice that this is an FCC Structure")
+//the lattice parameter for highest bragg's angle is
+//a=lambda*sqrt(h^2+k^2+l^2)/(2*sin(theta))
+//here h^2+k^2+l^2=19
+//and let h^2+k^2+l^2 =M for notation
+M=19
+a=lambda*sqrt(M)/(2*sin(theta6))  //A
+printf ("lattice parameter of material is %f A",a)