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+//chapter 16
+//example 16.2
+//page 475
+clear all;
+clc ;
+//given
+Eo=20;//supply voltage
+Eomin=Eo-1;
+Eomax=Eo+1;
+theta1=asin(Eomin/Eomax);//in radians
+theta=(theta1*180)/%pi;//in degrees
+T=1000/60;//in  ms
+T1=T *180/360;
+T2=T1/2;//time for 90 degrees
+T3=T*theta/360;//time for theta
+t1=T1+T2+T3;//total time in ms
+t2=1.17; //ms
+Il=40;//mA
+//diode peak repetitive current
+Ifm=ceil(Il*(t1+t2)/t2);//mA
+//diode avg forward current
+Io=Il;
+Vp=Eomax+0.7;//Vf=0.7V
+//diode maximum reverse voltage
+Er = 2 * Vp
+printf("\nIFM(rep)=%d mA",Ifm)
+printf("\nFor 1n4001,\nVr=50 V\nIo=1 A\nIFM=10 A\nThis is suiatable for required application.")
+Ifmsurge=30;
+printf("\nIFM(surge)=%d A",Ifmsurge)
+Rs=Vp/Ifmsurge;
+printf("\nRs=%.1f ohm",Rs);