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+//CHAPTER 7- SINGLE PHASE TRANSFORMER
+//Example 35
+
+disp("CHAPTER 7");
+disp("EXAMPLE 35");
+
+//single phase 50 hz, 200kVA, 11kVA/230 V
+//open circuit and short circuit tests
+//VARIABLE INITIALIZATION
+va=200000;                              //apparent power
+v1=11000;                               //primary voltage in Volts
+v2=230;                                 //secondary voltage in Volts
+Woc=1600;                               //watts also equals core losses
+Wc=2600;                               //watts, also equals cu losses
+f=50;
+//no load parameters
+//day cycle given
+h1=8;                                   // hours
+load1=160000;                           //load in watts
+pf1=0.8;                                //power factor
+h2=6;
+load2=100000;
+pf2=1;
+h3=10;
+load3=0;
+pf3=0;
+//SOLUTION  
+//24 hr energy output
+Pout=load1*h1*pf1+load2*h2*pf2+load3*h3*pf3;
+Pc24=Woc*24;                            // 24 hours Pc loss
+//cu loss= hours.(kva output/kva rated)^2.Full load Cu loss
+Pcu24=h1*(load1/va)^2*Wc+h2*(load2/va)^2*Wc+h3*(load3/va)^2*Wc;
+Pin=Pout+Pc24+Pcu24; 
+eff=Pout*100/Pin;
+//disp(sprintf("The value Pout is %f",Pout));
+//disp(sprintf("The value Pc is %f",Pc24));
+//disp(sprintf("The value Pcu is %f",Pcu24));
+disp(sprintf("The percent efficiency at full load is %.2f",eff)); 
+disp(" "); 
+// 
+//END