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+//CHAPTER 3- THREE-PHASE A.C. CIRCUITS
+//Example 6
+
+disp("CHAPTER 3");
+disp("EXAMPLE 6");
+
+//VARIABLE INITIALIZATION
+v_l=3300;                     //line voltage in Volts
+p_out=1500*735.5;             //output power in Watts (1 metric horsepower= 735.498W)
+eff=0.85;
+pow_fact=0.81;
+
+//SOLUTION
+
+//solution (a)
+p_in=p_out/eff;
+disp(sprintf("(a) The motor input is %.2f kW",p_in/1000));
+
+//solution (b)
+I=p_in/(sqrt(3)*v_l*pow_fact);//phase current = line current for star connection
+disp(sprintf("(b) The line and phase current of the alternator is %.2f A",I));
+
+//solution (c)
+I_l=I;
+I_ph=I_l/sqrt(3);             //phase current = (line current)/sqrt(3) for delta connection
+disp(sprintf("(c) The line current of the motor is %.2f A",I_l));
+disp(sprintf("The phase current of the motor is %.2f A",I_ph));
+
+//Answers may be different due to precision of floating point numbers
+
+//END
+
+
+