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+//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
+//Example 9
+
+disp("CHAPTER 2");
+disp("EXAMPLE 9");
+
+
+//VARIABLE INITIALIZATION
+V=120;                        //voltage of lamp in Volts
+P=100;                        //in Watts
+Vsupp=220;                    //supply voltage in Volts
+f=50;                         //in Hertz
+//Equations to be used
+//Z=R+jXl
+//Vsupply=V+jVl=sqrt(V^2+Vl^2)
+//Hence Vl=sqrt(Vsupply^2-V^2)
+//P=VI
+//Xl=2.pi.f.L
+
+//SOLUTION
+Vl=sqrt((Vsupp^2)-(V^2)); 
+Xl=(V*Vl)/P;
+L=Xl/(2*%pi*f);			//inductance
+disp(sprintf("The pure inductance should have a value of %6.4f H",L)); //text book answer is 0.7046 H
+
+//END