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Diffstat (limited to '1445/CH2/EX2.23/Ex2_23.sce')
| -rw-r--r-- | 1445/CH2/EX2.23/Ex2_23.sce | 24 |
1 files changed, 9 insertions, 15 deletions
diff --git a/1445/CH2/EX2.23/Ex2_23.sce b/1445/CH2/EX2.23/Ex2_23.sce index 7ff187786..c570e9471 100644 --- a/1445/CH2/EX2.23/Ex2_23.sce +++ b/1445/CH2/EX2.23/Ex2_23.sce @@ -1,38 +1,32 @@ //CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT -//Example 22 // read it as example 22 in the book on page 2.76 +//Example 22 (mentioned as 'example 22' in the book) +clc; disp("CHAPTER 2"); disp("EXAMPLE 23"); -//Given -//Equation of an Ac current with respect to origin -//i=100.sin2.pi.50t -//i=100.sin 100.pi.t -// //VARIABLE INITIALIZATION -A=100 //Amplitude in Amps -f=50 //frquency in Hz -t1=1/600 //sec after wave becomes zero again -a1=86.6 //amplitude at some time t after start +A=100 //amplitude in Amperes +f=50 //frequency in Hz +t1=1/600 //time in seconds after wave becomes zero again +a1=86.6 //amplitude in Amperes at some time 't' after start + //SOLUTION //solution (a) //Amplitude at 1/600 second after it becomes zero -// w=f*2*%pi; //angular speed hp=1/(2*f); //half period, the point where sine beomes zero again after origin -//The hald period , hp, needs to be added to 1/600 sec t=hp+t1; a2=A*sin(w*t); disp("SOLUTION (a)"); -disp(sprintf("Amplitude after 1/600 sec is %3.0f A", a2)); +disp(sprintf("Amplitude after 1/600 sec is %3f A", a2)); disp(" "); //solution (b) //since A=A0.sinwt, t=asin(A/A0)/w t2=(asin(a1/A))/w; disp("SOLUTION (b)"); -disp(sprintf("The time at which amp would be %3.2f is %3.3f sec", a1,t2));//text book answer is 1/300 sec -// +disp(sprintf("The time at which amp would be %f is %3f sec", a1,t2)); //END |