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+//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
+//Example 22 // read it as example 22 in the book on page 2.76
+
+disp("CHAPTER 2");
+disp("EXAMPLE 23");
+
+//Given
+//Equation of an Ac current with respect to origin 
+//i=100.sin2.pi.50t
+//i=100.sin 100.pi.t
+//
+//VARIABLE INITIALIZATION
+A=100                           //Amplitude in Amps
+f=50                            //frquency in Hz 
+t1=1/600                        //sec after wave becomes zero again
+a1=86.6                         //amplitude at some time t after start
+//SOLUTION
+
+//solution (a)
+//Amplitude at 1/600 second after it becomes zero
+//
+w=f*2*%pi;                      //angular speed
+hp=1/(2*f);                     //half period, the point where sine beomes zero again after origin
+//The hald period , hp, needs to be added to 1/600 sec
+t=hp+t1;
+a2=A*sin(w*t);
+disp("SOLUTION (a)");
+disp(sprintf("Amplitude after 1/600 sec is %3.0f A",  a2)); 
+disp(" "); 
+//solution (b)
+//since A=A0.sinwt, t=asin(A/A0)/w
+t2=(asin(a1/A))/w;
+disp("SOLUTION (b)");
+disp(sprintf("The time at which amp would be  %3.2f is  %3.3f  sec", a1,t2));//text book answer is 1/300 sec
+// 
+
+//END
+
+