diff options
Diffstat (limited to '1445/CH2/EX2.11/Ex2_11.sce')
| -rw-r--r-- | 1445/CH2/EX2.11/Ex2_11.sce | 31 |
1 files changed, 10 insertions, 21 deletions
diff --git a/1445/CH2/EX2.11/Ex2_11.sce b/1445/CH2/EX2.11/Ex2_11.sce index ba0618572..2ac6e7fd2 100644 --- a/1445/CH2/EX2.11/Ex2_11.sce +++ b/1445/CH2/EX2.11/Ex2_11.sce @@ -1,6 +1,7 @@ //CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 11 +clc; disp("CHAPTER 2"); disp("EXAMPLE 11"); @@ -8,29 +9,17 @@ disp("EXAMPLE 11"); vdc=100; //DC voltage in Volts vac=100; //AC voltage in Volts f=50; //in Hertz -Idc=10; //dc current in Amperes -Iac=5; //ac current in Amperes - -// coil means a unit of resistence and inductance both -//Impedence Z=R+jXl -//when DC supply is connected to coil, it behaves like a short circuit -//Xl=2.pi.f.L -//since f=0 in DC, Xl=0 ohms -//Therefore, R=Vdc/I - -//Equation to be used -//Z^2=R^2+Xl^2 +I1=10; //in Amperes +I2=5; //in Amperes //SOLUTION -r=vdc/Idc; //resistance of the coil in dc circuit -z=vac/Iac; //impedance of the coil in Ac supply -xl=sqrt((z^2)-(r^2)); // inductive reactance of coil -L=xl/(2*%pi*f); //inductance of the coil -pf=r/z; // power factor pf=R/Z -// -disp(sprintf("The inductive reactance of the coil is %5.2f Ohm",xl)); -disp(sprintf("The inductance of the coil is %4.2f H",L));//text book answer is 0.05 H -disp(sprintf("The power factor of the coil is %3.1f (lagging)",pf)); +r=vdc/I1; +z=vac/I2; +xl=sqrt((z^2)-(r^2)); +L=xl/(2*%pi*f); +pf=r/z; +disp(sprintf("The inductance of the coil is %f H",L)); +disp(sprintf("The power factor of the coil is %f (lagging)",pf)); //END |