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+//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS 
+//Example 7
+
+disp("CHAPTER 1");
+disp("EXAMPLE 7");
+
+//VARIABLE INITIALIZATION
+I1=1;                           //current source in Amperes
+v1=4;                           //voltage source in Volts
+v2=3;                           //voltage source in Volts
+v3=6;                           //voltage source in Volts
+r1=2;                           //resistance in Ohms
+r2=2;                           //resistance in Ohms
+r3=1;                           //resistance in Ohms
+r4=3;                           //resistance in Ohms
+
+//SOLUTION
+//converting all the voltage sources into current souces
+I2=v1/r1;
+I3=v2/r3;
+I4=v3/r4;
+disp(sprintf("The four current sources are %d A, %d A, %d A and %d A",I1,I2,I3,I4));
+
+req1=(r1*r2)/(r1+r2);           // 2Ω and 2Ω are in parallel 
+req2=(r3*r4)/(r3+r4);           // 3Ω and 1Ω are in parallel
+v2=(I1+I4)*req1;
+v3=(I3-I2)*req2;
+req=req1+req2;
+v=v2+v3;
+I=v/req;
+disp("VOLTAGE EQUIVALENT CIRCUIT:");
+disp(sprintf("   Voltage source= %f V",v));
+disp(sprintf("   Equivalent resistance(in series)= %f Ω",req));
+disp("CURRENT EQUIVALENT CIRCUIT:");
+disp(sprintf("   Current source= %f A",I));
+disp(sprintf("   Equivalent resistance(in parallel)= %f Ω",req));
+
+//END
+
+
+
+
+