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+//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS 
+//Example 34
+
+disp("CHAPTER 1");
+disp("EXAMPLE 34");
+
+//VARIABLE INITIALIZATION
+I=10;                           //current source in Amperes
+v=10;                           //voltage source in Volts
+r1=4;                           //top resistance in Ohms
+r1=4;                           //right resistance in Ohms
+r3=4;                           //bottom resistance in Ohms
+r4=6;                           //left resistance in Ohms
+r5=1;                           //in Ohms
+
+//SOLUTION
+
+//activating the current source
+//(17)v1+(-12)v2=120.......eq (1)
+//(-4)v1+(6)v2=0...........eq (2)
+//solving the equations by matrix method
+A=[17 -12;-4 6];
+b=[120;0];
+x=inv(A)*b;
+v1=x(1,:);                       //to access the 1st element of 2X1 matrix
+v2=x(2,:);                       //to access the 1st element of 2X1 matrix
+if(v1>v2) then
+I1=(v1-v2)/r5;
+else
+I1=(v2-v1)/r5;
+end;
+
+//activating the voltage source
+//(17)v1+(-12)v2=30.......eq (1)
+//(-4)v1+(6)v2=10...........eq (2)
+//solving the equations by matrix method
+A=[17 -12;-4 6];
+b=[30;10];
+x=inv(A)*b;
+v3=x(1,:);                       //to access the 1st element of 2X1 matrix
+v4=x(2,:);                       //to access the 1st element of 2X1 matrix
+if(v3>v4) then
+I2=(v3-v4)/r5;
+else
+I2=(v4-v3)/r5;
+end;
+
+I_tot=I1+I2;
+disp(sprintf("By Superposition Theorem, the current through 1Ω resistor is %f A",I_tot));
+
+//END