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+//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS 
+//Example 19
+
+disp("CHAPTER 1");
+disp("EXAMPLE 19");
+
+//VARIABLE INITIALIZATION
+v=7;                            //voltage source in Volts
+I=7;                            //current source in Amperes
+r1=1;                           //in Ohms
+r2=2;                           //in Ohms
+r3=1;                           //in Ohms
+r4=2;                           //in Ohms
+r5=3;                           //in Ohms
+
+//SOLUTION
+//(1)I1+(-4)I2+(3)In=7.......eq (1)
+//(-1)I1+(6)I1+(-3)In=0......eq (2)
+//(0)I1+(1)I2+(-1)In=0.......eq (3)
+//solving the equations by matrix method
+A=[1 -4 3;-1 6 -3;0 1 -1];
+b=[7;0;0];
+x=inv(A)*b;
+I1=x(1,:);                      //to access the 1st element of 3X1 matrix
+I2=x(2,:);                      //to access the 2nd element of 3X1 matrix
+In=x(3,:);                      //to access the 3rd element of 3X1 matrix
+r=r1+r5;
+rn=(r*r4)/(r+r4);
+I=(rn*In)/(rn+r3);
+vx=-I*r3;   
+disp(sprintf("By Norton Theorem, the value of V_x is %d V",vx));
+
+//END