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+// Example 3.3
+// Calculating Power Transfer and Efficiency
+v_s=120; // Open Circuit Voltage
+R_s=0.2+4.8;// Source resistance
+R_L=5; // From Maximum Power transfer theorem
+P_max=(120)^2/(4*5); // Maximum Power Transfered
+P_hp=P_max/746;// Maximum Power in Horsepower
+i=120/(5+4.8+0.2);// Current in circuit
+P_s=(i)^2*5;// Power dissipated in Source
+Eff=P_max/(P_max+P_s); // Power Transfer Efficiency
+disp(P_max,"Maximum Power Transfered(in Watt)=")
+disp(P_hp,"Maximum Power Transfered(in Horsepower)=")
+disp(Eff,"Power Transfer Efficiency =")