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-rwxr-xr-x1370/CH3/EX3.14/example3_14.sce16
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diff --git a/1370/CH3/EX3.14/example3_14.sce b/1370/CH3/EX3.14/example3_14.sce
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+//example3.14
+clc
+disp("eta % =98% ,S= 200 kVA, cos(phi)=0.8, Iron loss=200 W")
+disp("Therefore, eta % = (200*10^3 *0.8*100)/(200*10^3 *0.8+2000+copper loss)")
+disp("0.98[200*10^3 *0.8+2000+copper loss]=200*10^3 *0.8")
+c=((200*800)/0.98)-((200*800)-2000)
+format(9)
+disp(c,"i)Copper loss at full load(in watt)=")
+disp("ii)Half load copper loss(in watt) = (n^2)*(W_cu)full load where n=0.5 as half load")
+x=(0.5^2)*1265.306
+format(8)
+disp(x,"=(0.5^2)*1265.306 =")
+disp("Efficiency at half load = (100*10^3 *0.8*100)/(100*10^-3 *0.8+2000+316.326)")
+n=(100*800*100)/((0.8*100000)+2000+316.326)
+format(7)
+disp(n,"eta % = ")