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+printf("\t example 20.2 \n");
+printf("\t approximate values are mentioned in the book \n");
+T1=150; // F
+T2=220; // F
+L=0.6; // ft
+N=7500; // rev/hr
+row=62.5; // lb/ft^3
+mu=1.06; // at 150 F and from fig 14, lb/ft*hr
+k=0.38; // Btu/(hr)*(ft^2)*(F/ft), from table 4
+c=1; // Btu/(lb)*(F)
+Rej=(L^2)*(N)*(row)/(mu);
+printf("\t Rej is : %.1e \n",Rej);
+Z=1; // Z=(mu/muw)^(0.14), regarded as 1 for water
+Dj=1.01; // ft, from table 11
+j=1700; // fig 20.2
+hi=((j)*(k/Dj)*((c*mu/k)^(1/3))*(Z)^(0.14));
+printf("\t hi is : %.0f Btu/(hr)*(ft^2)*(F) \n",hi);
+hoi=1500; // Btu/(hr)*(ft^2)*(F)
+Uc=((hi*hoi)/(hi+hoi)); // from eq 6.38
+printf("\t Uc is : %.0f Btu/(hr)*(ft^2)*(F) \n",Uc);
+Rd=0.005;
+hd=(1/Rd);
+printf("\t hd is : %.0f \n",hd);
+UD=((Uc*hd)/(Uc+hd));
+printf("\t UD is : %.1f Btu/(hr)*(ft^2)*(F) \n",UD);
+Q=32600;
+A=(Q/(UD*(T2-T1)));
+printf("\t Area is : %.2f ft^2 \n",A);
+a=0.1309; // ft^2/ft
+a1=(3.14*0.8*a);
+printf("\t area per turn is : %.3f ft^2 \n",a1);
+n=(A/a1);
+printf("\t number of turns : %.1f \n",n);
+// end