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+printf("\t example 19.4 \n");
+eS=0.9; // assumed
+TG=1500;
+TS=650;
+pCO2=0.1084;
+pH2O=0.1248;
+printf("\t approxiate values are mentioned in the book \n");
+L=(0.4*8.5)-(0.567*5); // table 19.1
+printf("\t L is : %.3f ft \n",L);
+pH2OL=0.1248*L;
+pCO2L=0.1084*L;
+printf("\t pH2OL is : %.4f atm-ft \n",pH2OL);
+printf("\t pCO2L is : %.4f atm-ft \n",pCO2L);
+qH2O=1050; // at TG, from fig 19.12 ana 19.13
+qCO2=1700; // at TG, from fig 19.12 ana 19.13
+qTG=(qH2O+qCO2);
+printf("\t qTG is : %.0f \n",qTG);
+qsH2O=165; // at TS, from fig 19.12 ana 19.13
+qsCO2=160; // at TS, from fig 19.12 ana 19.13
+qTS=(qsH2O+qsCO2);
+printf("\t qTG is : %.0f \n",qTS);
+q=(0.9*(qTG-qTS)); // q=(QRC/A)
+printf("\t q is : %.1f \n",q);
+P=((pCO2)/(pCO2+pH2O));
+printf("\t percentage correction at P : %.3f \n",P);
+Pt=pCO2L+pH2OL;
+printf("\t Pt is : %.4f \n",Pt);
+// %correction estimated to be 2%
+q1=(q*0.98); // // q1=(QRC/A)
+printf("\t q1 is : %.2e \n",q1);
+hr=(q1/(TG-TS));
+printf("\t radiation coefficient is : %.2f Btu/(hr)*(ft^2)*(F) \n",hr);
+//end
+
+