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+printf("\t example 15.6\n");
+printf("\t approximate values are mentioned in the book \n");
+//20000=WD+WB;
+//0.99*WD+(0.05*WB)=(20000*.5);
+// solving above two eq. we get WD and WB
+WD=9570; // lb/hr
+WB=10430; // lb/hr
+HBl=108; // fig 3 and 12
+HDl=85.8; //fig 3 and 12
+HDv=253.8; // fig 3 and 12
+HFl=92; // fig 3 and 12
+l=153; // fig 3 and 12
+QR=((2.54+1)*WD*(HDv))-(2.54*WD*HDl)+(WB*HBl)-(20000*HFl);
+printf("\t total heat duty : %.1e Btu/hr \n",QR);
+Q=QR/153;
+printf("\t total heat duty : %.2e lb/hr \n",Q);
+// end