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+//To find the minimum distance in which the car may be stopped
+clc
+//given
+w=9.5 //ft
+h= 2 //ft
+x=4 //ft
+v=30//mph
+V=1.46667*v//ft/s
+u1=.1
+u2=.6
+g=32.2//ft/s^2
+//a) rear wheels braked
+fa1=(u1*(w-x)*g)/(w+u1*h)
+fa2=(u2*(w-x)*g)/(w+u2*h)
+sa1=V^2/(2*fa1)
+sa2=V^2/(2*fa2)
+//b) front wheels braked
+fb1=u1*x*g/(w-u1*h)
+fb2=u2*x*g/(w-u2*h)
+sb1=V^2/(2*fb1)
+sb2=V^2/(2*fb2)
+//c) All wheels braked
+fc1=u1*g
+fc2=u2*g
+sc1=V^2/(2*fc1)
+sc2=V^2/(2*fc2)
+k1=(x+u1*h)/(w-x-u1*h)//Na/Nb
+k2=(x+u2*h)/(w-x-u2*h)//Na/Nb
+printf("\nCoefficient of friction = 0.1\na) Minimum distance in which car may be stopped when the rear brakes are applied = %.f ft\nb) Minimum distance in which car may be stopped when the front brakes are applied = %.f ft\nc) Minimum distance in which car may be stopped when all brakes are applied = %.f ft\nCoefficient of friction = 0.6\na) Minimum distance in which car may be stopped when the rear brakes are applied = %.f ft\nb) Minimum distance in which car may be stopped when the front brakes are applied = %.f ft\nc) Minimum distance in which car may be stopped when all brakes are applied = %.f ft\n",sa1,sb1,sc1,sa2,sb2,sc2)
+printf("Required ration of Na/Nb\nFor u1 = 0.1 -> %.3f\nFor u2 = 0.6 -> %.2f\n",k1,k2)