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+//To find the least effort applied at the end of the lever which will provide a braking torque of 4000 lb ft
+clc
+//given
+n=12
+u=.28
+a=4.5//in
+b=1//in
+l=21//in
+r=15//in
+Tb=4000//lb
+theta=10*%pi/180
+//k=Tn/To
+k=((1+u*tan(theta))/(1-u*tan(theta)))^n
+Q=Tb*(12/r)
+P=Q*(a-b*k)/(l*(k-1))//from combining 8.6 with k=e^u*theta
+printf("The least effort required = P = %.1f lb",P)